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Engineering Calculations Homework: Fluid Dynamics and Power, Assignments of Mechanical Engineering

Engineering calculations for various physical quantities, including fluid velocity, power, reynolds number, and shaft diameter. The calculations are based on given values for volumetric flow, force, diameter, angular velocity, and power. The document also includes the answers to the calculations.

Typology: Assignments

Pre 2010

Uploaded on 08/06/2009

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Name_____________________
MET 161 Engineering Calculation Homework
1 ft = 0.3048 meter 1 Newton = 0.2248 lbf (force) 1 gal = 231 in
3
1 mile = 5280 ft 1 gallon = 3.785 liter 1 atm = 14.696 psi
100 cm = 1 meter 1 kg = 2.205 lbm (mass) 1 Acre = 43560 ft
2
1 inch = 2.54 cm 1 hp = 550 ft lbf/s 1 radians = 0.1592 rev
1 BTU = 777.6 ft lbf 1 meter = 39.37 inches 1 bar = 10
5
Pa
1 kg = 0.0685 slug 1° Kelvin = 1.8° Rankin 1 mile = 1.609 km
1 Stoke = 1 cm
2
/s 1 Poise = 1 dyne sec/cm
2
1 Newton = 10
5
dyne
Calculate all quantities to 4 S.F.
1. Compute fluid velocity, v (ft/s) where:
volumetric flow, Q= 100 gpm
v = 4Q_ conductor diameter, D = 3 in
πD2
2. Compute power (kW) where:
force, F = 3500 N
power = F * v velocity, v = 100 km/hr
3. Compute Reynolds number, NR where:
(dimensionless) volumetric flow, Q= 100 gpm
diameter, D = 3 in
N
R = Q * D * w weight density, w = 0.9*62.425 lbf/ft3
ν * g * A absolute viscosity, ν = 0.1858 lbfs/ft2
gravity, g = 32.2 ft/s2
Area, A = πD2/4
4. Compute shaft diameter, D (in) where:
power = 25 kW
D = (power/ ω/ shear modulus) angular velocity, ω = 1750 rpm
shear modulus = 3000 lbf/in2
5. Pressure Head, h (ft) where:
pressure, p = 1 MPa
h = p/w weight density, w = 56 lbf/ft3
Answers: 1. v=4.539 ft/s; 2. power=97.22 kW; 3. NR=10.66; 4. D=0.7384 inches; 5. h=372.9 ft

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Name_____________________

MET 161 Engineering Calculation Homework

1 ft = 0.3048 meter 1 Newton = 0.2248 lbf (force) 1 gal = 231 in^3 1 mile = 5280 ft 1 gallon = 3.785 liter 1 atm = 14.696 psi 100 cm = 1 meter 1 kg = 2.205 lb (^) m (mass) 1 Acre = 43560 ft^2 1 inch = 2.54 cm 1 hp = 550 ft lbf /s 1 radians = 0.1592 rev 1 BTU = 777.6 ft lbf 1 meter = 39.37 inches 1 bar = 10 5 Pa 1 kg = 0.0685 slug (^1) ° Kelvin = 1.8° Rankin 1 mile = 1.609 km 1 Stoke = 1 cm 2 /s 1 Poise = 1 dyne sec/cm^2 1 Newton = 10^5 dyne

Calculate all quantities to 4 S.F.

  1. Compute fluid velocity, v (ft/s) where: volumetric flow, Q= 100 gpm v = 4Q_ conductor diameter, D = 3 in πD^2
  2. Compute power (kW) where: force, F = 3500 N power = F * v velocity, v = 100 km/hr
  3. Compute Reynolds number, NR where: (dimensionless) volumetric flow, Q= 100 gpm diameter, D = 3 in NR = Q * D * w weight density, w = 0.9*62.425 lb (^) f /ft 3 ν * g * A absolute viscosity, ν = 0.1858 lbf s/ft 2 gravity, g = 32.2 ft/s^2 Area, A = πD^2 /
  4. Compute shaft diameter, D (in) where: power = 25 kW D = (power/ ω/ shear modulus)⅓^ angular velocity, ω = 1750 rpm shear modulus = 3000 lbf /in^2
  5. Pressure Head, h (ft) where: pressure, p = 1 MPa h = p/ w weight density, w = 56 lb (^) f /ft 3

Answers: 1. v=4.539 ft/s; 2. power=97.22 kW; 3. N (^) R =10.66; 4. D=0.7384 inches; 5. h=372.9 ft