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Calculating Displacement and Distance Traveled of a Body with Changing Velocity, Summaries of Physics

Solutions to calculate the total distance traveled and displacement of a body whose velocity changes direction over time. It includes three examples with different velocity functions and time intervals.

Typology: Summaries

2021/2022

Uploaded on 09/12/2022

barnard
barnard 🇺🇸

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DISPLACEMENT vs. DISTANCE TRAVELED
If a body with position function s (t) moves along a coordinate line without changing direction,
we can calculate the total distance it travels from t = a to t = b. If the body changes direction one
or more times during the trip, then we need to integrate the body's speed |v (t)| to find the total
distance traveled.
FACT:
FACT:
EXAMPLE 1:
Find the total distance traveled by a body and the body's
displacement for a body whose velocity is v (t) = 6sin 3t on the
time interval 0 t /2.
SOLUTION: To find the distance traveled, we need to find the values of t where the function
changes direction. To do this, set v (t) = 0 and solve for t.
t = 0 is the starting point, and t = 2 /3 is not in the time interval. Now to determine which
direction the body is going on the time intervals (0, /3) and ( /3, /2).
(0, /3)
v ( /4) > 0
( /3, /2)
v (5 /12) < 0
So to find the total distance traveled, I will have two integrals. One will have to be taken times a
-1 to make it positive.
Displacement will be the integral from 0 to /2.
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DISPLACEMENT vs. DISTANCE TRAVELED

If a body with position function s (t) moves along a coordinate line without changing direction, we can calculate the total distance it travels from t = a to t = b. If the body changes direction one or more times during the trip, then we need to integrate the body's speed |v (t)| to find the total distance traveled.

FACT:

FACT:

EXAMPLE 1: Find the total distance traveled by a body and the body's displacement for a body whose velocity is v (t) = 6sin 3t on the time interval 0  t   /2.

SOLUTION: To find the distance traveled, we need to find the values of t where the function changes direction. To do this, set v (t) = 0 and solve for t.

t = 0 is the starting point, and t = 2 /3 is not in the time interval. Now to determine which direction the body is going on the time intervals (0,  /3) and ( /3,  /2).

(0,  /3) v ( /4) > 0

( /3,  /2) v (5 /12) < 0

So to find the total distance traveled, I will have two integrals. One will have to be taken times a -1 to make it positive.

Displacement will be the integral from 0 to  /2.

EXAMPLE 2: Find the total distance traveled by a body and the body's displacement for a body whose velocity is v (t) = 49 - 9.8t on the time interval 0  t  10.

SOLUTION: Again, we need to determine if the body changes direction during its travels.

v (t) = 0  49 - 9.8t = 0  9.8t = 49  t = 5

(0, 5) v (4) > 0

(5, 10) v (6) < 0

On the interval where the velocity is negative, I will have to multiply the integral by a - 1 to make the distance positive.

EXAMPLE 3: Find the total distance traveled by a body and the body's displacement for a body whose velocity is v (t) = 6t 2 - 18t + 12 = 6(t - 1)(t - 2) on the time interval 0  t  3.

SOLUTION: Just like the previous examples, we have to determine where the velocity changes direction, but it is easier this time since we are given the factored form the velocity. The velocity changes direction at t = 1 and t = 2.

(0, 1) v (0.5) > 0

(1, 2) v (1.5) < 0

(2, 3) v (2.5) > 0