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Determination of Kc for a Complex Ion Formation
Objectives
Find the value of the equilibrium constant for formation of FeSCN2+^ by using the visible light absorption of the complex ion. Confirm the stoichiometry of the reaction.
Background
In the study of chemical reactions, chemistry students first study reactions that go to completion. Inherent in these familiar problems—such as calculation of theoretical yield, limiting reactant, and percent yield—is the assumption that the reaction can consume all of one or more reactants to produce products. In fact, most reactions do not behave this way. Instead, reactions reach a state where, after mixing the reactants, a stable mixture of reactants and products is produced. This mixture is called the equilibrium state ; at this point, chemical reaction occurs in both directions at equal rates. Therefore, once the equilibrium state has been reached, no further change occurs in the concentrations of reactants and products.
The equilibrium constant, K , is used to quantify the equilibrium state. The expression for the equilibrium constant for a reaction is determined by examining the balanced chemical equation. For a reaction involving aqueous reactants and products, the equilibrium constant is expressed as a ratio between reactant and product concentrations, where each term is raised to the power of its reaction coefficient ( Equation 1). When an equilibrium constant is expressed in terms of molar concentrations, the equilibrium constant is referred to as Kc. The value of this constant at equilibrium is always the same, regardless of the initial reaction concentrations. At a given temperature, whether the reactants are mixed in their exact stoichiometric ratios or one reactant is initially present in large excess, the ratio described by the equilibrium constant expression will be achieved once the reaction composition stops changing.
a A (aq) + b B (aq) c C (aq) + d D (aq)
Kc
C
c (^) D
d
^ A
a (^) B
(^) b Equation 1
We will be studying the reaction that forms the reddish-orange iron (III) thiocyanate complex ion, Fe(H 2 O) 5 SCN2+^ ( Equation 2a ). The actual reaction involves the displacement of a water ligand by thiocyanate ligand, SCN–.
Fe(H 2 O) 6 3+^ ( aq ) + SCN–^ ( aq ) Fe(H 2 O) 5 SCN2+^ ( aq ) + H 2 O ( l ) Equation 2a
For simplicity, and because water ligands do not change the net charge of the species, water can be omitted from the formulas of Fe(H 2 O) 6 3+^ and Fe(H 2 O) 5 SCN2+; thus Fe(H 2 O) 6 3+^ is usually written as Fe3+^ and Fe(H 2 O) 5 SCN2+^ is written as FeSCN2+^ ( Equation 2b). Also, because the concentration of liquid water is essentially unchanged in an aqueous solution, we can write a simpler expression for Kc that expresses the equilibrium condition only in terms of species with variable concentrations.
Fe3+^ ( aq ) + SCN–^ ( aq ) FeSCN2+^ ( aq )
Kc
FeSCN 2
^ Fe 3 ^ SCN
Equation 2b
In this experiment, students will create several different aqueous mixtures of Fe3+^ and SCN–. Since this reaction reaches equilibrium nearly instantly, these mixtures turn reddish-orange very quickly due to the formation of the product FeSCN2+^ (aq). The intensity of the color of the mixtures is proportional to the concentration of product formed at equilibrium. As long as all mixtures are measured at the same temperature, the ratio described in Equation 2b will be the same.
Measurement of [FeSCN2+]. Since the complex ion product is the only strongly colored species in the system, its concentration can be determined by measuring the intensity of the orange color in equilibrium systems of these ions. Two methods (visual inspection and spectrophotometry) can be employed to measure the equilibrium molar concentration of FeSCN2+, as described in the Procedure section. Your instructor will tell you which method to use. Both methods rely on Beer's Law ( Equation 3 ). The absorbance, A , is directly proportional to two parameters: c (the compound's molar concentration) and path length,
(the length of the sample through which the light travels). Molar absorptivity , is a constant that expresses the absorbing ability of a chemical species at a certain wavelength. The absorbance, A , is roughly correlated with the color intensity observed visually; the more intense the color, the larger the absorbance.
A c Equation 3
In the visual inspection method, you will match the color of two solutions with different concentrations of FeSCN2+^ by changing the depth of the solutions in a vial. As pictured in Figure 1, the solution on the left is more concentrated than the one on the right. However, when viewed from directly above, their colors can be made to "match" by decreasing the depth of the more concentrated solution. When the colors appear the same from above, the absorbances, A , for each solution are the same; however, their concentrations and path lengths are not.
Figure 1: Solution depths (path lengths) of two samples containing different
concentrations of FeSCN2+^ can be adjusted so that their apparent color looks
the same when viewed from above.
Table 1: Reaction ICE Table Fe3+^ + SCN–^ FeSCN2+ I nitial Concentration [Fe3+]i [SCN–]i 0 C hange in Concentration – x – x + x E quilibrium Concentration [Fe3+]i – x [SCN–]i – x x = [FeSCN2+]
The reaction "ICE" table demonstrates the method used in order to find the equilibrium concentrations of each species. The values that come directly from the experimental procedure are found in the shaded regions. From these values, the remainder of the table can be completed.
Standard Solutions of FeSCN2+. In order to find the equilibrium [FeSCN2+], both methods require the preparation of standard solutions with known [FeSCN2+]. These are prepared by mixing a small amount of dilute KSCN solution with a more concentrated solution of Fe(NO 3 ) 3. The solution has an overwhelming excess of Fe3+, driving the equilibrium position far towards products. As a result, the equilibrium [Fe3+] is very high due to its large excess, and therefore the equilibrium [SCN–] must be very small. In other words, we can assume that ~100% of the SCN–^ is reacted meaning that SCN–^ is a limiting reactant resulting in the production of an equal amount of FeSCN2+^ product. Examine the Kc-expression to prove this to yourself. In summary, due to the large excess of Fe3+^ , the equilibrium concentration of FeSCN2+^ can be approximated as the initial concentration of SCN–.
Procedure
Safety : The iron(III) nitrate solutions contain nitric acid. Avoid contact with skin and eyes; wash hands frequently during the lab and wash hands and all glassware thoroughly after the experiment. Collect all your solutions during the lab and dispose of them in the proper waste container.
Materials and Equipment
Solutions : Iron(III) nitrate (2.00 x 10–^3 M) in 1 M HNO 3 ; Iron(III) nitrate (0.200 M) in 1 M HNO 3 ; Potassium thiocyanate (2.00 x 10–^3 M). Materials :
Procedure C. Test tubes (large and medium size), stirring rod, 5-mL volumetric pipet, 10- mL graduated pipet, flat-bottomed glass vials (6), Pasteur pipets, ruler
Procedure D. Test tubes (large and medium size), stirring rod, 5-mL volumetric pipet, 10- mL graduated pipet, Pasteur pipets, ruler, spectrometers and cuvets* (2).
*must obtain from stockroom
A. Solution Preparation Label two clean, dry 50-mL beakers, and pour 30-40 mL of 2.00 x 10–^3 M Fe(NO 3 ) 3 (already dissolved by the stockroom in 1 M HNO 3 ) into one beaker. Then pour 25-30 mL of 2.00 x 10–^3 M KSCN into the other beaker. At your work area, label five clean and dry medium test tubes to be used for the five test mixtures you will make. Using your volumetric pipet, add 5.00 mL of your 2.00 x 10–^3 M Fe(NO 3 ) 3 solution into each of the five test tubes. Next, using your graduated pipet, add the correct amount of KSCN solution to each of the labeled test tubes, according to the table below. Rinse out your graduated pipet with deionized water, and then use it to add the appropriate amount of deionized water into each of the labeled test tubes. Stir each solution thoroughly with your stirring rod until a uniform orange color is obtained. To avoid contaminating the solutions, rinse and dry your stirring rod after stirring each solution
Table 2: Test mixtures Mixture Fe(NO 3 ) 3 solution KSCN solution water 1 5.00 mL 5.00 mL 0 mL 2 5.00 mL 4.00 mL 1.00 mL 3 5.00 mL 3.00 mL 2.00 mL 4 5.00 mL 2.00 mL 3.00 mL 5 5.00 mL 1.00 mL 4.00 mL
Five solutions will be prepared from 2.00 x 10–^3 M KSCN and 2.00 x 10–^3 M Fe(NO 3 ) 3 according to this table. Note that the total volume for each mixture is 10.00 mL, assuming volumes are additive. If the mixtures are prepared properly, the solutions will gradually become lighter in color from the first to the fifth mixture. Use this table to perform dilution calculations to find the initial reactant concentrations to use in Figure 3.
B. Preparation of a Standard Solution of FeSCN2+ Before examining the five test mixtures, prepare a standard solution with known concentration of FeSCN2+. Obtain 15 mL of 0.200 M FeNO 3. (Note the different concentration of this solution.) Rinse your volumetric pipet with a few mL of this solution, and add 10.00 mL of this solution into a clean and dry large test tube. Using your graduated pipet, add 8.00 mL deionized water to the large test tube. Rinse your graduated pipet with a few mL of 2.00 x 10–^3 M KSCN. Then add 2.00 mL of the KSCN solution to the large test tube. Mix the solution with a clean and dry stirring rod until a uniform dark-orange solution is obtained. This solution should be darker than any of the other five solutions prepared previously.
C. Determination of [FeSCN2+] by visual inspection
Note: Skip to part D if your instructor asks you determine [FeSCN2+] spectrophotometrically.
Label five flat-bottomed vials to be used for each of the five test mixtures prepared earlier. Using a clean and dry Pasteur (dropping) pipet, transfer each solution into the properly labeled vial. Rinse the dropping pipet between solutions with a small portion of the next solution to be added. The volume of the solution transferred to the vials is not important; you will obtain the best results by nearly filling each of the vials. Label a sixth vial to be used for the standard solution.
Rinse your dropping pipet with a small portion of the standard solution. Then add the standard solution to the sixth labeled vial until it is about one-third full. Place this vial next to the vial
Name: Course Section: Instructor:
Lab Report: Determination of Kc for a Complex Ion Formation
Experimental Data
Initial Concentrations of Fe3+^ and SCN–^ in Unknown Mixtures (Part A)
Tube
Reagent Volumes (mL) Initial Concentrations (M) 2.00 x 10-^3 M Fe(NO 3 ) 3
2.00 x 10-^3 M KSCN Water^ Fe
3+ SCN–
Show a sample dilution calculation for [Fe3+]initial in Tube #1 only.
The Standard FeSCN2+^ Solution (Visual Method, Parts B and C)
10.00 mL of 0.200 M Fe(NO 3 ) 3 2.00 mL of 0.00200 M KSCN 8.00 mL of water
Equilbrium [FeSCN2+] in Standard Solution: M Note that since [Fe3+]>>[SCN–] in the Standard Solution, the reaction is forced to completion, thus causing all the SCN–^ to convert to FeSCN2+.
Show the stoichiometry and dilution calculations used to obtain this value.
Equilibrium Concentrations of FeSCN2+^ in Mixtures (Visual Method, Part C)
Tube
Solution Depths (mm) [FeSCN2+]equil (M)
Show a sample calculation for Mixtures Standard^ [FeSCN2+]equil^ in Tube #1 only.
1
2
3
4
5
Calculations and Analysis
The reaction that is assumed to occur in this experiment is:
Fe3+^ ( aq ) + SCN–^ ( aq ) FeSCN2+^ ( aq )
Write the equilibrium constant expression for the reaction.
Create a Reaction Table (or ICE table), as in Table 1 , to demonstrate how the values below are calculated. Use the data for Mixture #1 only. Start with the known values for the initial concentrations of each species and the final value of [FeSCN2+] from the data table on the previous page. Show how you find the value of the stoichiometric change in reaction concentrations that occurs, and the resulting equilibrium concentrations of the reactants.
Show a sample calculation for the value of Kc using the data for Tube #1.
Using the same method you outlined above, complete the table for all the equilibrium
concentrations and value of Kc.
Tube
Equilibrium Concentrations (M) Fe3+^ SCN–^ FeSCN2+ Kc
1
2
3
4
5
Average value of Kc ________________ (Use reasonable number of significant digits, based on the distribution of your Kc values.)
Average value of Kc ________________ (Use a reasonable number of significant digits, based on the distribution of your Kc values.)
Based on the calculated values of Kc for each reaction stoichiometry, which reaction is the valid one?
Briefly explain your conclusion. Compare the percent difference between the average value and the individual measurements. What does this tell you about the two possible stoichiometries? Do these reactions give consistent values of Kc for different initial reaction conditions?
