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Đề lý năm 2011 PFIEV, Exams of Physics

Đề lý phân ngành năm 2011 PFIEV

Typology: Exams

2010/2011

Uploaded on 07/10/2023

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bg1
B~C
THI
PH~V
NG-
N&
2011
M~N
THI
:
VqT
L$!
Th&
gian
Z&m
b&i
:
120
phzir
J
-
Ciiu
1
:
(15
#it&)
-
Mot spi dfiy chi& dli 1, kh6i lugng kMng dhg k6, kMng
bi co dm.
Ngu&i
ta
gib
vlo
m@
&u ciia spi d$ chht di6m M c6
khgi lupng m vl buoc dku
kia
&a
spi
d8y vao chi m6c
A.
M6c
A quay xung quanh mc nh ngang
0
v6i v& t6c g6c khang d6i
w
. Khokg cach
til
m6c
A
t6i
trgc quay
0
bhg
r
(xem
hi
1).
,,
B6
qua moi ma'siit.
HHy thi6t l@p phucmg
Mnh
vi phiin m6
tii
chuy&n dong cfia
chit di6m
M
khi dhg d@ 1at dong luc hgc trong he qui chi&
+.
phi
GALILEE.
Cho
:
rwL
-<<I
;
B<<1
g
Clu
2
:
(15
dih)
-
Mot sqi day khhg
&,
dai 1, kh6i lupng kh8ng dSng
k&.
Hai
chit di&m
MI
va
M2 c6 kbgi lupng ml vl m2.
Ngufri
ta
luh spi day qua
a&
chi 18
0
ch& di&m thuoc
--
mat phhg nh ngang P
(0,
ex, e,
)
vl
gh
2
chht di6m MI, M2 vlo
2
dku sgi day. Ma
sat @a sqi day vii 16 kh6ng dang k6. Cac chht
di&m
MI, M2 buoc phHi
truqt
k.ng ma
sit, M2 tren trgc &ing
ddimg
(0,
<)
huhg xu6ng du(ri, MI tren mat phibg nhn
ngang P. Lfic t
=
0, M2 duqc bu8ng ra khBng v@n t6c ban dhu vh MI,
(r
A
sao cho
-
-
OA
=
r,
,
c6 mot v@n tbc
6
tqrc giao xuyen
tgm
(
yb
vuBng g6c v(ri
<
).
@em
hi
2).
11 Tim bibu thuc cfia
vo
d& M2 dhg yen. Trong
cac di&u ken dc6, chuy&n dong ciia MI nhu th6 nho?
U
Xtrc d@ th6 nbg
hi&
dwg
Gdr)
cfia he.
Chon ghc th6 nhg
E,
$i
0
bbg 0.
Ciiu
3
:
(30
dilm)
-
-
HINH2
Mot lupng hoi nubc
vira
dhg bHo hba khbi luqng m
=
1 kg ban ddu duqc giir
Z1
trqng thsj A-c6
iip
sub PA
=
15,55
bar, nhiet do tA
=
200°C vl cho dHn dbg entropi
dkn tqmg thSj cuBi (trgng thai B) cc6 tip sub
Ps
=
1,O
13
bar, nhiet 66 tB
=
1 OO°C.
11 Hay bib di8n qub
trinh
bi6n thi&n tr&n gih
db
entropi (T,
S)
khi he di
tii
trgng thiri ddu dkn trgng thsi cu6i bhg cach sir dwg ciic dubng dbg
$
PA,
PB
va
duhg cong biio hba.
21 Hiiy
$
dung nguyen 19
I1
nhiet dong hoc d& tim bi&u ththirc entropi bikn ddi
trgng thai ri6ng hhoi
-
16ng
&
nhiet do Te (d6i vbi biin ddi thub nghich).
Tu
11 va 21 hay:
pf2

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B ~ C THI P H ~ VNG- N& 2011

M ~ THIN : VqT L$!

Th& gian Z&m b&i : 120 phzir

Ciiu 1 : (15 #it&)^ J^ -

  • Mot spi dfiy chi& dli 1, kh6i lugng kMng d h g k6, kMng bi co dm. Ngu&i ta gib vlo m@ &u ciia spi d$ chht di6m M c

khgi lupng m v l buoc dku kia &a spi d8y vao chi m6c A. M6c

A quay xung quanh m c n h ngang 0 v6i v& t6c g6c khang d6i w. Khokg cach til m6c A t6i trgc quay 0 b h g r (xem h i 1). (^) ,, B6 qua moi ma'siit. HHy thi6t l@pphucmg Mnhvi phiin m6 tii chuy&ndong cfia chit di6m M khi d h g d@ 1 a t dong luc hgc trong he qui chi& +. phi GALILEE.

Cho : -<<I rwL ; B<< g

Clu - 2 : (15 d i h ) Mot sqi day k h h g &,dai 1, kh6i lupng kh8ng dSng k&.Hai chit di&mMI va M2 c6 kbgi lupng ml v l m2. Ngufri ta l u h spi day qua a& chi 18 0 ch& di&mthuoc -- mat p h h g n h ngang P (0, ex,e, ) v l gh 2 chht di6m MI, M2 vlo 2 dku sgi day. Ma sat @a sqi day vii 16 kh6ng dang k6. Cac chht di&m MI, M2buoc phHi truqt k. n g ma sit, M2 tren trgc &ing ddimg (0, <) h u h g xu6ng du(ri, MI tren mat phibg nhn ngang P. - - Lfic t = 0, M2 duqc bu8ng ra khBng v@nt6c ban dhu vh MI, (r A sao cho OA = r, ,c6 mot v@ntbc 6 tqrc giao xuyen tgm (yb vuBng g6c v(ri <). @em h i 2). 11 Tim bibu thuc cfia vo d&M2 d h g yen. Trong cac di&uken dc6, chuy&ndong ciia MI nhu th6 nho? U Xtrc d@ th6 n b g hi& d w g Gdr) cfia he.

Chon ghc th6 n h g E,$i 0 b b g 0.

Ciiu - 3 : (30 dilm) - HINH

Mot lupng hoi nubc vira d h g bHo hba khbi luqng m = 1 kg ban ddu duqc giir Z

trqng thsj A-c6 iip s u b PA = 15,55 bar, nhiet do tA = 200°C v l cho dHn d b g entropi

dkn tqmg thSj cuBi (trgng thai B) cc 6 tip sub Ps = 1 ,O 13 bar, nhiet 66 tB= 1 OO°C.

11 Hay b i b di8n qub trinh bi6n thi&ntr&ng i h db entropi (T, S) khi he di tii trgng thiri ddu dkn trgng thsi cu6i b h g cach sir d w g ciic dubng d b g $ PA, PB va d u h g cong biio hba. 21 Hiiy $ dung nguyen 19 I1 nhiet dong hoc d&tim bi&uththirc entropi bikn ddi

trgng thai ri6ng hhoi - 16ng & nhiet do Te (d6i vbi biin ddi t h u b nghich).

Tu 11 va 21 hay:

31 X6c dinh him luqng nuirc lbng rieng xl (r trwg th6i c d i ; Cho bikt : * cl = 4,18 KJ/kg.K dgi v6i nu& lbng vh gigis. thikt r h g nhiet dung

ri& kh6ng phu th@c n h i t do dpc the0 d u b g cong d i b sumg ir g i h db (T, S).

  • entanpi rihg c h su bay hai mx6c :

lh(TA)='I 942 KJ/kgy lb(TB)= 225 5 KJIkg.

41 Xac d m bikn thidn entanpi ri&ngtrong qua Mnh bi&ndbi.

-51Gii thi& r h g hoi nu6c c6 tinh chit nhu khi 19 tuhg, chit 16ng duqc xem

nhu kh6ng nkq h a n g d h duqc vh vl<< vb. HHy xbc d w c6ng t h u b nghich trao dbi

vh @ bikn thiC noi n h g trong qua trhh tren. Cho bikt MM, = 18g ,h h g s6 khi

R = 8,3 1 J1mol.K w.mFA L a. A e K

-^ CSu^^4 :^ (20diim)^. l/ a/ Hay vikt 4 phurrng trinh MAXWEU trmg c h h k&g du6i &g tich phiin vh vi p h h trong he qui chi& GALILEE. b/ N&u 9 nghia cila m8i phuong trinh vh cfia cH h& h m g Mnh MAXWELL.

21 Mot 6ng dfiy t h h g dsi v6 h v g8m n vbng q 1 k& nhau tren don vi d8i

quanh hinh tr(l bhn kinh a, t n ~ c(OZ). Cho dbng di&n i(t) chpy trong 6ng diiy.

a/ Tim bi&uthirc cSla thk vectu 2 kkt hpp v6i ttr tnrbng caa dbng dien i(t)

chqy trong 6ng d8y trong m6c do COULOMB (duqc bp dyng tqrc tikp c%ngthf~ctinh

N tnrhg cfia 6ng d Q dien t h h g dlii v8 hw). bl XBc dinh d i e t r u h g cHm img b&i dbng d i b bi6n t h i h i(t).

d Tim th6ng lupag cca vectcr POYNTING di qua hinh trp tr(lc (OZ), chiku

cao h, b8n khh a. Tir kkt q d nh& dugc hHy cho nhnhgn x6t.

CBU 7 5 : (20 didm)

Mot &a dk @n mbng coi nhu trp trbn dbc, t n ~ c

I ./ ,

(OZ), b8n kinh a, bb dhy e. Dia m a g dien tich Q vh khgi f''< : a / + \

lupng rn (Q vh m dugc p h h b6 dku theo d tich). Dia c6 (^) I Q 7 I th& quay do quanh trpc (OZ). 3). IXa duqc

n h h g trong ttr trubng diu bikn dbi the0 th&i gian

L,"

B = B(t)e,. 1/6thbidi&nt=0Ntrutmg tangnhanhtilgiiitri

'7 H~NH 3

0 dkn Bo. Tim b i h thirc van t6c g6c quay cu, c b &a khi

ttr truhg &t gi8 hj Bo.

21 Tim he thirc lien he momen tir dm dia dang quay v6i tir t r u h g mh n6 chiu thc

dwg.