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Rational Expressions and Algebraic Fractions, Lecture notes of Physics

A comprehensive guide on rational expressions, including factoring, adding and subtracting fractions, dividing by rational expressions, and the remainder theorem. It also covers algebraic fractions, proper fractions, and partial fractions. Additionally, the document discusses parametric equations and their conversion to Cartesian equations, as well as transforming parametric graphs through translation, stretching, and reflection.

What you will learn

  • What is the remainder theorem and how is it used to determine if a rational expression is a factor of another?
  • How do you factor rational expressions?
  • How do you convert parametric equations to Cartesian equations?

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CORE 4 Summary Notes
1 Rational Expressions 1
· Factorise all expressions where possible
· Cancel any factors common to the numerator and denominator
x
2
+ 5x =x(x + 5)
x
2
25
(
x + 5
)
(
x 5
)
=x
x 5
· To add or subtract - the fractions must have a common denominator
6+
x
3
x x
(
4
)
= 6(x 4)
x x 4
(
)
+3
x x
(
4
)
= 6x 24 + 3
x x 4
(
)
= 6x 21
x x 4
(
)
· To divide by a rational expression you can multiply by it’s reciprocal.
2 Rational Expressions
· REMAINDER THEOREM
When p(x) is divided by (ax-b) the remainder is p( b
a)
Note that x = b
ais the solution of the equation ax – b = 0
E.g Show that 2x –1 is a factor of
2x
3
+ 7x
2
14x + 5
2x – 1 =0
x = 0.5
2(0·5)
3
+ 7(0·5)
2
14(0·5) + 5 = 0
Must be a factor as
the remainder is zero
· An Algebraic fraction is ‘PROPER’ is the degree of the polynomial that is the
numerator is less than the degree of the polynomial that is the denominator.
x + 6
x + 2 =x + 2 + 4
x + 2
=x + 2
x + 2 +4
x + 2 = 1 + 4
x + 2
E.g.1
x
2
+ 6x 3
x + 2 =(x + 2)(x + 4) 11
x + 2
= x + 4 11
x + 2
2
x
3
2x
2
+ x + 5
x
2
3 =(x
2
3)(x 2) + 4x 1
x
2
3 = x 2 + 4x 1
x
2
3
3
· An identity is a statement that is true for all values of x for which the
statement is defined
1
www.mathsbox.org.uk
pf3
pf4
pf5
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pf9

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CORE 4 Summary Notes

1 Rational Expressions 1

∑ Factorise all expressions where possible

∑ Cancel any factors common to the numerator and denominator

x

2

+ 5x

x(x + 5)

x

2

  • 25 (x + 5)(x – 5)

x

x – 5

∑ To add or subtract - the fractions must have a common denominator

x

x x –( 4 )

6(x – 4)

x x – 4( )

x x –( 4 )

6x – 24 + 3

x x – 4( )

6x – 21

x x – 4( )

∑ To divide by a rational expression you can multiply by it’s reciprocal.

2 Rational Expressions

∑ REMAINDER THEOREM

When p(x) is divided by (ax-b) the remainder is p(

b

a

Note that x =

b

a

is the solution of the equation ax – b = 0

E.g Show that 2x –1 is a factor of 2x

3

+ 7x

2

  • 14x + 5

2x – 1 =

x = 0.

3

2

  • 14(0·5) + 5 = 0

Must be a factor as

the remainder is zero

∑ An Algebraic fraction is ‘PROPER’ is the degree of the polynomial that is the

numerator is less than the degree of the polynomial that is the denominator.

x + 6

x + 2

x + 2 + 4

x + 2

x + 2

x + 2

x + 2

x + 2

E.g.

x

2

+ 6x – 3

x + 2

(x + 2)(x + 4) – 11

x + 2

= x + 4 –

x + 2

x

3

  • 2x

2

+ x + 5

x

2

  • 3

(x

2

  • 3)(x – 2) + 4x – 1

x

2

  • 3

= x – 2 +

4x – 1

x

2

  • 3

∑ An identity is a statement that is true for all values of x for which the

statement is defined

∑ PARTIAL FRACTIONS

Any proper algebraic fraction with a denominator that is a product of distinct

linear factors can be written as partial fractions as the sum of proper fractions

whose denominators are linear factors.

5x + 1

(x – 1)(2x + 1)(x – 5)

can be expressed in the form

A

x – 1

B

2x + 1

C

x – 5

E.g

(x – 2)(x + 3)

A

x – 2

B

x + 3

A(x + 3) + B(x – 2)

(x – 2)(x + 3)

Looking at the numerators A(x + 3) + B(x - 2) = 5

x= 2 5A = 5 so A = 1

x= -3 -5B = 5 so B = -

REPEATED FACTOR

5x + 1

(x 1 )(2x + 1)

2

can be expressed in the form

A

x – 1

B

2 x + 1

C

(2x + 1)

2

3 Parametric Equations

∑ Two equations that separately define the x- and y- coordinates of a graph in terms

of a third variable.

∑ The third variable is called the parameter

x = t + 4 y = 1 – t

2

∑ To convert a pair of parametric equations to single Cartesian equation, eliminate the

parameter.

E.g.

x = t + 4 t = x – 4 so t

2

= x

2

  • 8x + 16

y = 1 – t

2

y = 1 – (x

2

  • 8x + 16)

y = 8x – x

2

  • 15

∑ CIRCLE and ELLIPSE

The curve x = r cos q y = r sin q is a circle with radius r and centre the origin

The curve (^) x = rcos q (^) + p y = r sin q (^) + p is a circle with radius r and centre (p,q)

The curve x = acos q y = bsin q is an ellipse, centre the origin.

Its width is 2a and its height is 2b units.

∑ For an expansion of an expression such as

x + 5

split the expression into

(3 – x)(1 + 3x)

PARTIAL FRACTIONS before attempting an expansion.

5 Trigonometric Formulae

tan(A + B) =

tanA + tanB

1 – tanA tanB

ADDITION FORMULAE

sin (A+B) = sin A cos B + sin B cos A

sin (A-B) = sin A cos B – sin B cos A

cos (A+B) = cos A cos B – sin A sin B

tan(A – B) =

tanA – tanB

1 + tanA tanB

cos (A-B) = cos A cos B + sin A sin B

DOUBLE ANGLE FORMULAE

sin 2A = 2sin A cos A

cos 2A = cos

2 A –sin

2 A = 2 cos

2 A –1 = 1 – 2sin

2 A

tan 2A =

2tanA

1 – tan

2

A

∑ asin x + bcos x can be written in the form

rsin(x + a) where a = rcos a and b = rsin a

rcos(x – a) where a = rsin a and b = rcos a

r

2

= a

2

+ b

2

e.g Find the maximum value of the expression 2 sin x + 3 cos x by expressing it in

the form

rsin(x + a)

rsin a^

3

rcos a 2

tan a =

3

2

a = 56

r

2 = a

2

  • b

2

r

2

= 2

2

  • 3

2

= 13

r = 13

2sinx + 3cosx = (^) 13 sin(x + 56)

Maximum value is 13 which occurs when sin(x+56) =1 x = 34

∑ asinx – bcos x can be written in the form

rsin(x – a), where a = rcosa and b = rsina

rcos(x + a), where a = – rsina and b = – rcosa

r

2

= a

2

+ b

2

∑ Both of the above are useful in SOLVING EQUATIONS.

6 Differential Equations

∑ Key points from core 3

The derivative of e

ax

is ae

ax

Ú

e

ax

dx =

e

ax

+ c

a

Ú

ax

dx =

lnÁax + bÁ + c

+ b a

Ú

f '(x)

dx = lnÁf(x)Á + c

f (x )

Ú

a

2

+ x

2

dx =

a

tan

  • 1 Ê

Ë

Á

x ˆ

a

+ c

Ú

a

2

  • x

2

dx = sin

  • 1 Ê x

Ë

Á

a

+ c

∑ An equation that involves a derivative is called a Differential Equation. They are

used to model problems involving rates of change.

e.g The rate of growth of a population is proportional to the size of the population.

Let the population at time t to be P

dP

= kP where k is a constant

dt

∑ SEPARATING THE VARIABLES – a method of solving differential equations.

Find the general solution of dy^ = 2x(y + 4) y > 0

  1. Separate the variables

dx

dy

y + 4

= 2x dx

  1. Integrate both sides

Ú

1

y + 4

dy =

Ú

2x dx

ln(y + 4) = x

2

  • c

y + 4 = e

x

2

  • c = e

x

2

e

c = Ae

x

2

where A = e

c

y = Ae

x 2

  • 4

∑ USING TRIGONOMETRICAL IDENTITIES

Ú

sin x cos x dx =

Ú

sin 2 x

cos 2 x + c

Using the identity

2sinx cosx = sin 2x

Using the identity Ú

cos

2

Ú

x dx = (c

os 2 x + 1) dx

cos 2x = 2cos

2 x -

Replacing x by ½ x in the identity

Ú

si n

2

Ú

cos 2

x dx =

  • cos x )

x = 1 – 2sin

2

x

9 Vectors

∑ A vector has two properties :

Magnitude (or size)

and Direction

∑ Vectors with the same magnitude and direction are equal.

∑ The modulus of a vector is its magnitude.

The modulus of the vector a is written |a|

∑ Any vector parallel to the vector a may be written as (^) l a where (^) l is a non-zero

real number and is sometimes called a scalar multiple of a.

  • a has the same magnitude but is in the opposite direction to a.

∑ Vectors can be added and subtracted using the ‘triangle law’.

∑ Vectors can be written in column vector form such as

Ë

Ê

Á

3

- 7

∑ A unit vector is a vector with a magnitude of 1.

The vectors i, j and k are unit vectors in the direction of the x-, y- and z- axes

respectively.

As column vectors i =

Ë

, j = , k =

Ê

Á

1 ˆ

0

0 ¯

Ë

Ê

Á

0 ˆ

1

0 ¯

Ë

Ê

Á

0 ˆ

0

1 ¯

Vectors can be written as linear combinations of these unit vectors,

e.g.

Ë

= 3 i – 7 j + k

Ê

Á

3 ˆ

  • 7

The magnitude (or modulus) of the vector Ë

= 3 i – 7 j + k is

Ê

Á

3 ˆ

  • 7

1 ¯

2

  • ( – 7)

2

  • 1

2

The distance between two points (x1, y1, z 1 ) and (x2, y2, z 2 ) is

( x 2

  • x 1

2

  • ( y 2
  • y 1

2

  • ( z 2
  • z 1

2

∑ For every point P there is a unique vector

OP

(where O is a fixed origin) which is

called the position vector of the point P.

The point with coordinates (x, y, z) has position vector Ë

Ê

Á

x ˆ

y

z ¯

For two points A and B with position vectors OA and OB the vector AB is

given by

∑ The general form of a vector equation of a line is

r (^) = p (^) + l d

r is the position vector of any point on the line,

p is the position vector of a particular point on the line,

l is a scalar parameter,

d is any vector parallel to the line (called a direction vector )

N.B. Since p and d are not unique then your equation might not

look identical to the one given in the back of the book!