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Concentration of Solutions and Molarity, Study notes of Chemistry

To calculate the molarity of a solution, divide the moles of solute by the volume of the solution. Remember that volume is ALWAYS in LITERS! Page 3. Molarity ...

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Concentration of Solutions and Molarity
The concentration of a solution is a measure of
the amount of solute that is dissolved in a given
quantity of solvent.
A dilute solution is one that contains a small
amount of solute.
Aconcentrated solution contains a large
amount of solute.
What we need is a way of quantifying the
concentration of a solution!
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Concentration of Solutions and Molarity

The concentration of a solution is a measure of

the amount of solute that is dissolved in a given

quantity of solvent.

  • A dilute solution is one that contains a small

amount of solute.

  • A concentrated solution contains a large

amount of solute.

What we need is a way of quantifying the

concentration of a solution!

Molarity ( M ) is the number of moles of solute

dissolved in one liter of solution.

  • To calculate the molarity of a solution, divide the moles of solute by the volume of the solution. Remember that volume is ALWAYS in LITERS!

Molarity Example

What is the molarity of 600. mL of potassium

iodide solution that contains 5.50 moles of

the solute?

M = mol solute / L soln.

M = 5.50 mol / .600 L

M = 9.16 molar

1. 05 mol_NaClO

x

x

L

mol M

Molarity Example

What volume of a 4.0 M solution would

contain 15.5 moles of sodium thiosulfate?

M = mol solute / L solution... so...

L = mol / M

L = 15.5 mol / 4.0 M

L = 3.9 liters of solution

2. What mass of sodium iodide (NaI) is contained in

250 mL of a 0.500M solution?

a) 150 g

b) 75.0 g

c) 18.7 g

d) 0.50 g mol 18.7g

(0.125mol)149.89g

x 0.125_mol_NaI

0.250L

0.5M x

Making a Dilute Solution

a) To prepare 100 ml of 0.40 M MgSO 4 from a stock solution of 2.0 M MgSO 4 , a student first measures 20 mL of the stock solution with a 20-mL pipet. b) She then transfers the 20 mL to a 100-mL volumetric flask. c) Finally she carefully adds water to the mark to make 100 mL of solution.

  • Volume-Measuring Devices

buret

graduated cylinder

volumetric flask

pipette

3. Diluting a solution does NOT change which of the

following?

a) concentration

b) volume

c) milliliters of solvent

d) moles of solute

Colligative Properties of Solutions

The wood frog is a remarkable creature because it

can survive being frozen. Scientists believe that a

substance in the cells of this frog acts as a natural

antifreeze, which prevents the cells from freezing.

You will discover how a solute can change the

freezing point of a solution.

a) In a pure solvent, equilibrium is established between the liquid and the vapor. b) In a solution, solute particles reduce the number of free solvent particles able to escape the liquid. Equilibrium is established at a lower vapor pressure.

Vapor pressure lowering--The decrease in a solution’s vapor pressure is proportional to the number of particles the solute makes in solution.

a) Three moles of glucose dissolved in water produce 3 mol of particles because glucose does not dissociate.

b) Three moles of sodium chloride dissolved in water produce 6 mol of particles because each formula unit of NaCl dissociates into two ions.

3 moles Na+ and 3 moles Cl-