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chemical process industries and calculation, Cheat Sheet of Chemical Processes

to whom it may concern and it is all original and it is very precise document which is written through many research paper

Typology: Cheat Sheet

2015/2016
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Uploaded on 10/21/2021

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Calculation
Basis of calculation
Degree of freedom on overall system
Unknown 4 200 kg of beans
Independent 3
DOF 1
Degree of freedom on Extractor
Unknown 3
Independent 3
DOF 0
Degree of freedom on Filter
Unknown 7
Independent 4
DOF 3
Degree of freedom on Evaporator
Unknown 3
Independent 3
DOF 0
Mass balance on Extractor
mass input through system - mass output from the system+ generation within the system-consupmtion within the system = accumulation within the system
There is no reaction take place and so the system in steady state that's why the generation, consumption and accumulation trem is zero
Mass input
Mass of Hexane 600
m1(kg C6H14)
Extractor
13.0 kg oil
87.0 kg S
600 kg
C6h14
m2(kg)
x2(kg S/kg)
y2(kg oil/kg)
1-X2-y2(kgC6H14)
m6 kgC6H14
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Calculation

Basis of calculation Degree of freedom on overall system Unknown 4 200 kg of beans Independent 3 DOF 1 Degree of freedom on Extractor Unknown 3 Independent 3 DOF 0 Degree of freedom on Filter Unknown 7 Independent 4 DOF 3 Degree of freedom on Evaporator Unknown 3 Independent 3 DOF 0 Mass balance on Extractor mass input through system - mass output from the system+ generation within the system-consupmtion within t There is no reaction take place and so the system in steady state that's why the generation, consumption and ac Mass input Mass of Hexane 600 m1(kg C6H14)

Extractor

13.0 kg oil 87.0 kg S 600 kg C6h m2(kg) x2(kg S/kg) y2(kg oil/kg) 1-X2-y2(kgC6H14) m6 kgC6H

Mass of Solid 87 Mass of Oil 13 Mass output m2? m2 700 Solid balance on Extractor x2*m2 87 13 x2 0. y2 0. Mass balance on Filter

Solid balance on Filter 87 S kg=0.75m m3 116 Mass balance on Filter m2=m3+m m4=m2-m3 0. m4 584 600 Oil balance on filter 29 m2y2 = m3y3+m4y4 613 13=116y3+584y4 - Hexane Balance on Filter m2(1-y2-x2)=m3(0.25-y3)+m4(1-y4) 600=29-m3y3+m4-m4y 600=29-116y3+584-584y 600-613=-116y3-584y 13=116(Y3)+584(Y4) y 2 *m 2