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to whom it may concern and it is all original and it is very precise document which is written through many research paper
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Basis of calculation Degree of freedom on overall system Unknown 4 200 kg of beans Independent 3 DOF 1 Degree of freedom on Extractor Unknown 3 Independent 3 DOF 0 Degree of freedom on Filter Unknown 7 Independent 4 DOF 3 Degree of freedom on Evaporator Unknown 3 Independent 3 DOF 0 Mass balance on Extractor mass input through system - mass output from the system+ generation within the system-consupmtion within t There is no reaction take place and so the system in steady state that's why the generation, consumption and ac Mass input Mass of Hexane 600 m1(kg C6H14)
13.0 kg oil 87.0 kg S 600 kg C6h m2(kg) x2(kg S/kg) y2(kg oil/kg) 1-X2-y2(kgC6H14) m6 kgC6H
Mass of Solid 87 Mass of Oil 13 Mass output m2? m2 700 Solid balance on Extractor x2*m2 87 13 x2 0. y2 0. Mass balance on Filter
Solid balance on Filter 87 S kg=0.75m m3 116 Mass balance on Filter m2=m3+m m4=m2-m3 0. m4 584 600 Oil balance on filter 29 m2y2 = m3y3+m4y4 613 13=116y3+584y4 - Hexane Balance on Filter m2(1-y2-x2)=m3(0.25-y3)+m4(1-y4) 600=29-m3y3+m4-m4y 600=29-116y3+584-584y 600-613=-116y3-584y 13=116(Y3)+584(Y4) y 2 *m 2