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CHEM 103 Portage Learning Module 2 Exam Questions and Verified Answer (2025/2026) Accurate, Exams of Nursing

University of PikevilleNursing

CHEM 103 Portage Learning Module 2 Exam Questions and Verified Answer (2025/2026) Accurate This document includes all verified questions and answers for Module 2 of CHEM 103 from Portage Learning. Covered topics include periodic trends, ionic and covalent bonding, Lewis structures, and molecular geometry. Each answer has been carefully reviewed to ensure accuracy, offering students a dependable tool to prepare effectively for the exam.

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CHEM 103 Module 2 Exam Portage Learning
Questions and Verified Answers,100% Guaranteed Pass
CHEM 103
MODULE:2 2025/2026
CHEM 103 M2: Exam Questions and Correct Answers
Attempt History
Attempt Time Score
LATEST Attempt 1 112 minutes 100 out of 100
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Download CHEM 103 Portage Learning Module 2 Exam Questions and Verified Answer (2025/2026) Accurate and more Exams Nursing in PDF only on Docsity!

CHEM 103 Module 2 Exam Portage Learning

Questions and Verified Answers,100% Guaranteed Pass

CHEM 103

MODULE: 2 2025/

CHEM 103 M2: Exam Questions and Correct Answers

Attempt History

Attempt Time Score LATEST Attempt 1 112 minutes 100 out of 100 .

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table (https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal.

  1. Al 2 (SO 4 ) 3
  2. C 7 H 5 NOBr Your Answer:
  3. Al 2 (SO 4 ) 3 Al = 2 x 26.98 = 53. S = 3 x 32.07 = 96. O = 12 x 16.00 = 192

Question 1 10 /^10 pts

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table (https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Show the calculation of the number of moles in the given amount of the

Question 2 10 /^10 pts

following substances. Report your answerto 3 significant figures.

  1. 13.0 grams of (NH 4 ) 2 CO 3
  2. 16.0 grams of C 8 H 6 NO 4 Br Your Answer: Moles = grams / Molecular Weight
  3. 13.0 grams of (NH 4 ) 2 CO 3 Moles = 13.0 g / 96.094 = .135 moles of (NH 4 ) 2 CO 3 N = 2 x 14.01 = 28. H = 8 x 1.008 = 8. C = 1 x 12.01 = 12. O = 3 x 16 = 48 Molecular weight is 96. 2. 16.0 grams of C 8 H 6 NO 4 Br Moles = 16.0 g / 260.038 = .0615 moles of C 8 H 6 NO 4 Br C = 8 x 12.01 = 96. H = 6 x 1.008 = 6. N = 1 x 14.01 = 14. O = 4 x 16.00 = 64 Br = 1 x 79.90 = 79. Molecular weight of C 8 H 6 NO 4 Br = 260.

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table (https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Show the calculation of the number of grams in the given amount of the following substances. Report your answer to 1 place after the decimal.

  1. 1.05 moles of Ca 3 (PO 4 ) 2
  2. 1.18 moles of C 9 H 8 NO 4 Cl Your Answer: Grams = moles X molecular weight
  3. 1.05 moles of Ca 3 (PO 4 ) 2 Grams = 1.05 moles X 310.18 = 325.689 grams --> 325.7 grams of Ca 3 (PO 4 ) 2

Question 3 10 /^10 pts

Ca = 3 x 40.08 = 120. P = 2 x 30.97 = 61. O = 8 x 16.00 = 128 Molecular weight of Ca 3 (PO 4 ) 2 is 310.

  1. 1.18 moles of C9H8NO4Cl Grams = 1.18 moles X 229.614 = 270.944 grams --> 270.9 grams of C 9 H 8 NO 4 Cl C = 9 x 12.01 = 108. H = 8 x 1.008 = 8. N = 1 x 14.01 = 14. O = 4 x 16.00 = 64 Cl = 1 x 35.45 = 35. Molecular Weight of C 9 H 8 NO 4 Cl = 229.
    1. Grams = Moles x molecular weight = 1.05 x 310.18 = 325. grams
    2. Grams = Moles x molecular weight = 1.18 x 229.61 = 270. grams

(https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Show the calculation of the percent of each element present in the following compounds. Report your answer to 2 places after the decimal.

  1. Ca 3 (PO 4 ) 2
  2. C 9 H 8 NO 4 Cl Your Answer:
  3. Ca 3 (PO 4 ) 2 Ca = 3 x 40.08 = 120.24 / 310.18 (x100) = 38.76% Ca P = 2 x 30.97 = 61.94 / 310.18 (x100) = 19.97% P O = 8 x 16.00 = 128 / 310.18 (x100) = 41.27% O
  4. C 9 H 8 NO 4 Cl C = 9 x 12.01 = 108.09 /229.614 (x100) = 47.07% C H = 8 x 1.008 = 8.064 /229.614 (x100) = 3.51% H N = 1 x 14.01 = 14.01 /229.614 (x100) = 6.10% N O = 4 x 16 = 64 /229.614 (x100) = 27.87% O Cl = 1 x 35.45 = 35.45 /229.614 (x100) = 15.44% Cl
  1. %Ca = 3 x 40.08/310.18 x 100 = 38.76% %P = 2 x 30.97/310.18 x 100 = 19.97% %O = 8 x 16.00/310.18 x 100 = 41.27%
  2. %C = 9 x 12.01/229.61 x 100 = 47.08% %H = 8 x 1.008/229.61 x 100 = 3.51% %N = 1 x 14.01/229.61 x 100 = 6.10% %O = 4 x 16.00/229.61 x 100 = 27. %Cl = 1 x 35.45/229.61 x 100 = 15.44%

Ca = 38.76 % / 40.08 = .967065 / .64158 = 1.5 (x2) = 3 Ca P = 19.87% / 30.97 = .64158 / .64158 = 1 (x2) = 2 P O = 41.27% / 16.00 = 2.5793 / .64158 = 4 (x2) = 8 O Empirical Formula is Ca 3 P 2 O 8 38.76% Ca / 40.08 = 0.9671 / 0.6416 = 1.5 x 2 = 3 19.87% P / 30.97 = 0.6416 / 0.6416 = 1 x 2 = 2 41.27% O / 16.00 = 2.579 / 0.6416 = 4 x 2 = 8 โ†’ Ca 3 P 2 O 8

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table (https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Balance each of the following equations by placing coefficients in front of each substance.

  1. Al 2 (SO 4 ) 3 + Ca(OH) 2 โ†’ Al(OH) 3 + CaSO 4

Question 6 10 /^10 pts

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table

Question 7 10 /^10 pts

(https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Classify each of the following reactions as either: Combination Decomposition Combustion Double Replacement Single Replacement

  1. C 5 H 12 + 8 O 2 โ†’ 5 CO 2 + 6 H 2 O
  2. Zn + CuSO 4 โ†’ Cu + ZnSO 4
  3. 2 Fe + 3 Cl 2 โ†’ 2 FeCl 3 Your Answer:
  4. C 5 H 12 + 8 O 2 โ†’ 5 CO 2 + 6 H 2 O This is a combustion reaction. (CO2 and H2O in products; C, H, and O2 in reactants)
  5. Zn + CuSO 4 โ†’ Cu + ZnSO 4 This is a single replacement reaction. (Cu and Zn are switched; SO remains in its place)
  6. 2 Fe + 3 Cl 2 โ†’ 2 FeCl 3 This is a combination reaction (2 reactants; 1 product)

You may find the following resources helpful: Scientific Calculator (https://www.desmos.com/scientific) Periodic Table (https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_ Equation Table (https://portagelearning.instructure.com/courses/948/files/271474/download? download_frd=1) Show the calculation of the oxidation number (charge) of ONLY the atoms which are changing in the following redox equations. KMnO 4 + KI + H 2 O โ†’ KIO 3 + MnO 2 + KOH Your Answer: KMnO 4 + KI + H 2 O โ†’ KIO 3 + MnO 2 + KOH left side charges KMnO 4 K = +

Question 8 10 /^10 pts

Mn = + O = - 2 (x4) = - 8 KI K = + I = - 1 H 2 O H = + O = - 2 left side charges KIO 3 K = + I = + O = - 6 MnO 2 Mn = + O = - 4 KOH K = + O = - 2 H = + Mn changes from +7 to +4 (change of 3) ; Mn new coefficient would be 6 (simplified to 2 as new coeff. of Mn) I changes from - 1 to +5 (change of 6) ; I new coefficient would be 3 (simplified to 1 as new coeff. of I) These can be simplified from 3 and 6 to 1 and 2 since they can be multiplied into eachother; so the final balanced equation would look as follows: