Solution Manual Electric Circuit Analysis and Design ch 14, Exercises of Electronic Circuits Analysis

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nalysis and Design, 2™ edition olutions Manu: Chapter 14 Exercise Solutions #143 50 a Act = Co EI4t [ + (te) Yqulmax) = ¥* —Fyp,(sat) ~ Mp5, = Act = -49.949 Yiese (Min) =P" +P yg Sat) + Ven { sat) —Pop, . ‘We have: tact gx aT = tict amo, Trap =100 ph, b= 80 eAIV?, i = 40 wl /V?, Act a Ww AcL= = det = ~49. 943 ()= For M,: E44 iy 350= (Fes +h) So 50= S003, - 05)" = Van, = 08167 Vep,(sat) = 0816-05= 03164 Then ¥a{max) = ¥* -0316-0816=6*-LI3¥ For M,: BO Ip= 100 = (3 \asern Vy) So 100=1000(Va5,-05) => Vp, =08167 Vga (sat) = 0816-05 = 0316F Voy(min) =~ +0.3164+0316-0816=F -0.184 So P0184 <¥q, 37 -LiG ¥ El4.2 vo{miax) =F* — Vang Sat) ~Feoyo( sat) y, (min) = P~ +F/yc4{ sat) +P apg( 221) Now (a0/2)(25) +05=0816 Vana (808) = Venyq( sat) = 0316F So v,(max) = ¥* -0316-0316=7* —0632 Van = Fiaay Also 50 Foss = earaas TSOP = {10 ose Voy = onyiasy 7 OBIS Viggq(Sat) = 0.724 -05=0224V Vogal saz) = 0816-05 = 0.3167 So v,(min)=V" +0316+0.224 =~ +054 Then V" 4054 ¢v, <¥* -0.6327 500 Actfideal) = ~3> = -25 Within 0.1% => —25 + (0.001}(25) = Act = -24.975 —28 = 24.975 = oF ] Age 28 = 35 = o.0010 Aat 24.973 Aor = 25.974 E143 Acr{oa} a. Ay = ce 1 [Sete] Aot Ra 495 Aaz(oo) 1+ Bate = = 100 Act = Sr =e Acy = 99.90 L+ oT Ac{oo) = 100 dAct 100 = = =On% Ace ~ 10% igs = SBS Act = 99,90 ~ (0.0001)£89.90) => Agcy = 96.89 E14.6 Agi(so} — Ace 2) Ace oy t Aci{ea] Aculoo) “|, Acelsa) Ach rq Aselooh_, — Agz (oo) Soa.ou, = Aci —___ . Aci 1 Aeslee 1 Seale) Act Ach