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Solution Manual Electric Circuit Analysis and Design ch 12, Exercises of Electronic Circuits Analysis

This solution manual was provided by Maria Geven at Assam University for Electrical Circuital Analysis course. It includes: Percent, Change, Negligible, DC, AC, Analysis, Output, Resistance, Phase, Margin

Typology: Exercises

2011/2012

Uploaded on 07/06/2012

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Electronic Circuj is and Design, 2™ edition Solutions Manual Chapter 12 Exercise Solutions R126 Ay: fa = Ao fh E121 : * 4 ay 2 Ae. LO a ADs Tag fr 280% 1 > Aj(0} = 32 teapstoage tnt ! Ar L B= Fe pe eT OS 0.001 EL2T | Y= Vs -Vya = 100-99 1 mV => 3 = 0.0499 bo We Vein = a a Vo = Aue = Av = po > Au = S000 V/V AL, — ® jay > T7eoassy = Ga.c0g = L888 Vin = Be = = = SE 9 nia v/v E122 = = A Aur = Tad, ~ T+ (0.0198)(5000) 4r- ya Avy = su V/V Apt AsApaa b. Rip = Ri +8A,) = (8) + (0.0198)(5000)] A; = A(L— A;8) > Riy = SUOKN 4-4 - — Fa 4 1=A,s8 1 = (80)(0.0120) Ror = T+ AA. ~ 1+ (0.0158)(5000) = 2000 => Ray > 00 E123 4 A #128 1" Tyas a igetg— Tye 00-99 Sb BA wet tet 2 can it lb 5 Ay; A> i007” iF Acs T= piggy 7 Ac S000 A/A 8 = 0.009999 pale ee oe 8.089 9 = 0.0198 A/A tA 1 €A_ fA;\ aA Ag= nr "ata 77a) aw if" T+ AB T+ ($000)(0.0198) sas (18 = dip = 50 ASA Ay jor } (200% ‘ dA =e-_e- = St = 0.00% b Ry = Pea; = To (0.0188) 5000) => Ry > 509 Bin ' “a Roy = (L + BAi)Ra = [1 + (0.0198)(5000)](4) she al AL far) a4 pe fizaay 4 = (42) A + Bey = Atay dar ( AY _ Sx 10° A AY tr. (A) ~ coaory{ 100 ) Bie dA = Vs — Vp, = 100-99 = 1 mV = tm Ap= a tPA GA SAV ews 2 Tm 7 aes SAY Bandwidth = w(1 + @As) = wn( 2) = canyciay( 32) ws = (26)(10*) cad/oce a+ f = 10 ks pate gate = 19.8 V/A Ay = —4t- = — ee 1L+BAg | 14+ (19.8)(5) > Ags = 0.05 A/V = 50 mA/V