Solution Manual Electric Circuit Analysis and Design ch 8, Exercises of Electronic Circuits Analysis

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Electronic Circuit Analysis and Design, 2™ edition Solutions Manual Chapter § Exercise Solutions Eg. For Vps = 0, Jp(max) = SIZ 1.2 A= Ip{max} Far fp = 0 = Vps(max) = 4 V Maximum power whea ; Vos = “PMD C10 V and Ip 22 Be) 205.8 => Pp(max) = (12)(0.6) = 7.2 Wans no 2, % E8.2 a Veo =30V, Ves = 30-IcRe, IcVer = 10 ‘Maximum power at Vex = plec =15 lez Me Bat S015 =20~ 22, > R=250 => Maximum Power = ]0 W. b Veg =I8V, Tema = 2A Vez = TcR, O=18-2R. > BizisQ => Maximum Power = (1)(' E83 00 Lee OIE fo ao we Mo Maximum power at ceater of load line Pros = (0.05)(10) > Poe = 0.5 W E8.4 Power = ip - bps = {1)(12) = 12 wans & Tank = Tamb + P- @saknuma Taine = 25 ~ (12)(4) = Tijey = 13°C b. Tense = Think + P+ Cease meat Tease = 73+ (12)(1) => Tense = 88°C A. Ther = Teare +P bdereuce Teer = 85 + (12)(3) => Type = 120°C. EBS wor Tomy _ 200-23, a Jeunes ee SCI acne SD aed we 8Cr Pome « -———Tims = Tian mt © Faavneus + Deane msnk + Sea oam _ 200-35 “3840542 = Po mas = 29.2 0 Teese = Trane + Po mar(Geasemtat + Frnt arab} = 26 + (29.2)(0.5 +2) ae: => Tee