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BCHS 3304 For UH Exam 1, Exams of Biochemistry

University of Houston (UH)Biochemistry
Prof. Jian Liu

Biochemistry 1 Practice Exam for UH. Use it well to succeed.

Typology: Exams

2023/2024

Uploaded on 09/12/2024

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Practice Exam1, Biochemistry 3304, Spring 2015
1. Biochemistry is a broad field with overlap across many other scientific disciplines. Which of the
following would not have significant overlap with Biochemistry?
a. Cell Biology
b. Medicinal Chemistry
c. Immunology
d. None of the above because all overlap with Biochemistry.
2. How can functional groups enable interactions between biological molecules?
a. Complementarity of charge
b. Complementarity of reactivity
c. Complementarity of structure
d. All of the above can be important.
3. What is the following functional group?
R H
O
a. Carboxylic acid
b. Aldehyde
c. Thiol
d. Alcohol
4. What is the following functional group?
O
N
H
R
1
R
2
a. Carboxylic acid
b. Amide
c. Thiol
d. Alcohol
5. What is the following functional group?
RSH
a. Thiol
b. Thioester
c. Amide
d. Alcohol
1
pf3
pf4
pf5

Partial preview of the text

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  1. Biochemistry is a broad field with overlap across many other scientific disciplines. Which of the following would not have significant overlap with Biochemistry? a. Cell Biology b. Medicinal Chemistry c. Immunology d. None of the above because all overlap with Biochemistry.
  2. How can functional groups enable interactions between biological molecules? a. Complementarity of charge b. Complementarity of reactivity c. Complementarity of structure d. All of the above can be important.
  3. What is the following functional group?

R H

O

a. Carboxylic acid b. Aldehyde c. Thiol d. Alcohol

  1. What is the following functional group? O

N H

R (^1)

R (^2)

a. Carboxylic acid b. Amide c. Thiol d. Alcohol

  1. What is the following functional group?

R SH a. Thiol b. Thioester c. Amide d. Alcohol

  1. What is the following functional group?

O P

O

OH

R O R

a. Amide b. Thiol c. Phosphate diester d. Phosphate ester

  1. Compartmentation conferred what kind of advantage for early cellular organisms? a. Concentrated the molecules and reactants necessary for important biological processes. b. Diluted the molecules and reactants necessary for important biological processes. c. Separated the inside of the cell from the surrounding environment. d. None of the above.
  2. What is the underlying theory behind evolutionary processes? a. Evolution is not a goal-directed process. b. Random variation is exhibited among individuals. c. Evolution is a continual process. d. Organisms with beneficial traits (mutations) will survive and pass on these traits.
  3. Conservation of Energy is which Law of Thermodynamics? a. First Law b. Second Las c. Third Law d. None of the above.
  4. The Second Law of Thermodynamics defines what thermodynamic principle? a. Enthalpy b. Entropy c. Gibbs Free Energy d. Standard Free Energy.
  5. In a first aid heat pack, a salt solution is mixed with a solvent and undergoes crystallization in an exothermic reaction. What would you observe considering only this reaction? a. The reaction would become hot and the entropy decreases. b. The reaction would become cold and the entropy decreases. c. The reaction would become hot and the entropy increases. d. The reaction would become cold and the entropy increases.
  6. If you want to drive the reaction in Question 11 in the backward direction, what would you do? a. Increase the temperature b. Decrease the temperature c. Try to maintain the same temperature d. Temperature is not important
  1. What physical property of water is most responsible for its remarkable properties as a solvent? a. It can accept and donate protons in supporting biological catalytic processes and structures of biological molecules. b. It has a polar bent structure with both hydrogens and lone-pair electrons that can form hydrogen bonding networks. c. The density of water decreases upon freezing. d. All of the above
  2. What is the fundamental difference between hydrogen bonding in ice versus liquid water? a. The number of hydrogen bonds per water molecule is different in ice versus liquid water b. The orientation of water molecules in ice is different than in liquid water c. The structure of the hydrogen bonding network in water is much more dynamic than in ice. d. The density of ice is lower than that for water.
  3. Which of the following amino acid sidechains would not participate in hydrogen bonding? a. Tyrosine b. Phenylalanine c. Lysine d. Serine
  4. What would be the order of bond length from shortest to longest between covalent bonds, ionic bonds, hydrogen bonds, and van der Waals bonds? a. Ionic Bond > Hydrogen Bond > van der Waals > Covalent Bond b. Ionic Bond > Covalent Bond > Hydrogen Bond > van der Waals c. Covalent Bond > Hydrogen Bond > Ionic Bond > van der Waals d. Covalent Bond > Ionic Bond > Hydrogen Bond > van der Waals
  5. Why do hydrophobic molecules cluster together and separate from water in aqueous environments? a. Non-polar substances like oil interact with each other more strongly than with water. b. Polar water molecules prefer to hydrogen bond with other water molecules. c. Water molecules organize around non-polar molecules to release as many water molecules into bulk solvent as possible and increase entropy. d. Clustering of non-polar molecules together in an aqueous environment is favored by enthalpy.
  6. How does the hydrophobic effect impact the structure of proteins? a. Proteins form a globular structure to maximize the attraction between non-polar sidechains in an aqueous environment. b. Exclusion of water molecules from the hydrophobic interior of the protein releases water molecules into bulk water and contributes to the globular structure. c. The protein globular structure maximizes the presence of hydrophilic sidechains on the surface of the protein. d. Protein globular structure requires an organized water “shell” around the non-polar sidechains.
  1. Dialysis can be best described as which of the following? a. Movement of solvent molecules from regions of high concentration to regions of lower concentration. b. Movement of soluble molecules from regions of high concentration to regions of lower concentration. c. Movement of solvent molecules across a semipermeable membrane from regions of high concentration to regions of lower concentration. d. Movement of soluble molecules across a semipermeable membrane from regions of high concentration to regions of lower concentration.
  2. In the earliest phase of dialysis of a protein and salt solution inside a dialysis membrane bag, osmosis is responsible for what effect? a. The movement of water molecules into the protein and salt solution through the dialysis membrane. b. The movement of salt molecules out of the protein and salt solution through the dialysis membrane. c. The retention of the protein inside the dialysis membrane. d. None of the above.
  3. What is the pH of a solution of 0.0001M NaOH? a. 14 b. 10 c. 8 d. 4
  4. A solution of formic acid is 10% ionized at a pH of 2.7. Calculate the approximate pKa for this acid. a. 1. b. 2. c. 3. d. 4.
  5. You have 100ml of 0.1M MES buffer at the pH = 5.09. The pKa for MES is 6.09. How much 1M NaOH would you need to add to change the pH from 5.09 to 7.09? Do not concern yourself with dilution effects. a. 2 ml b. 4 ml c. 8 ml d. 10 ml
  6. H 2 CO 3 is a diprotic acid. The pKa for H 2 CO 3 is 6.35 and the pKa for HCO 3 -^ = 10.33. At pH = 5.35, what is the approximate relative quantities of H 2 CO 3 , HCO 3 -^ , and CO 3 2-^? a. 90 H 2 CO 3 , 10 HCO 3 -^ , and negligible CO 3 2- b. 99 H 2 CO 3 , 1 HCO 3 -^ , and negligible CO 3 2- c. 1 H 2 CO 3 , 90 HCO 3 -^ , and 10 CO 3 2- d. Negligible H 2 CO 3 , 75 HCO 3 -^ , and 25 CO 3 2-
  • (^) H 3 N C H

O

O -

  • (^) H 3 N C H

O

O -^

  • (^) H 3 N (^) C H

O

O

HO

  • (^) H 3 N C H

O

O -

N HN

NH 3 +

  1. What amino acids exhibit protonation/deprotonation states that are significant at physiological pH? a. C, K b. D, C c. H, E d. H, C
  2. What is the approximate pI for the peptide MEKVDRP. Because this is a peptide, assume the pKa for the amino terminus is 9.0 and the pKa for the carboxyl terminus is 3.5. a. 4. b. 6. c. 7. d. 9.