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Basic Integrals you need to know, Study notes of Calculus

University of North Alabama (UNA)Calculus
Prof. Jesse Prince-Lubawy

This sheet shows you how each basic integral is solved. This is very helpful for calculus II if you plan to take it in college. Taking it from someone who’s already complete the course, I would highly suggest becoming familiar with these, it would make your life so much easier trust me!

Typology: Study notes

2024/2025

Uploaded on 05/14/2025

keira-culver
keira-culver 🇺🇸

1 document

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bg1
Basic
Integrals
(calc
.
I
1
.
(xndX
=
y
+
Xn
+
+
C
:
nF
-
*
it
is
very
important
to
be
familiar
with
these
for
CalCUNUS
I
.
2
.
ScosaX
dX
=
1
sinax
+
it
will
make
the
class
go
much
easier
!
*
3
.
Staux
dx
=
In/secx)dX
+
c
4
.
94dX
=
((x)
+
C
5
.
/SinaxdX
=
1 coGaX
+
6
.
ScotXdX
=
InIsinx1
+
c
7
.
(seXaX
=
In/sex
++
anx)
+
c
8
.
ScsCXdX
=
-
InICsX
+
cotX)
+
C
9
.
JeaxdX
=
1
eax
+
C
&
10
.
/baxdX
=
any
bax
+
c
:
b
>
0
,
b
+
1
11
.
Sin
xdx
=
XInXX
+
C
pf3
pf4

Partial preview of the text

Download Basic Integrals you need to know and more Study notes Calculus in PDF only on Docsity!

Basic

Integrals

(calc.I

1. (xndX =

y

+ Xn+ + C :

nF -^ *^ it^ is^ very important

to be familiar with

these for CalCUNUS I.

2. ScosaX dX =

sinax + it will (^) make the class go much^ easier^!^ *

3. Staux dx = In/secx)dX +^ c

(^4).

94dX

= ((x) +^ C

5. /SinaxdX =

1 coGaX

(^6). ScotXdX = InIsinx1 +^ c

7 .(seXaX = In/sex ++anx) +^ c

8. ScsCXdX =^ - InICsX +^ cotX) +^ C

9 .JeaxdX =^1 eax +^ C

&

10. /baxdX =

any

bax +^ c :^ b >^0 , b + 1

11. Sin xdx = XInXX +^ C

(^12). (109bXdX = cup (XIUX

  • X) +^ C (^13). ) (^) zz - x2dX = Sint(X)

+ C

14 (xz. z2dX = +au

()

+ C

15 (xx2 (^). 22@X = SectX^

C

(^16). /Sin"XdX = XSin

X +^1 -xz =^ C (^17). 900s"XdX = XCOS"X1-X2 +^ C (^18). Stan "XdX =^ X+En+ X-1(n(

  • (^) x2) +^ C (^19). Ssec-Xdx = XSec"X- In(X +^ x2^ -1)^ +^ C (^20). /SinhxdX = coshy + (^21). Sc0sUxdX = sinhx +^ C (^22). /SechXdX = tanny +^ C (^23). (^) /CSCh2XdX = -cothX + (^) C

(^36) .COS3XdX = +sin

  • (^) Six + (^37). /sin3XaX = COS3X-COSX + C