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Báo cáo thí nghiệm vật lý bài 3 nhóm mình tổng hợp
Typology: Lab Reports
1 / 8
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BÁO CÁO 3 : XÁC ĐỊNH MÔMEN QUÁN TÍNH CỦA TRỤC ĐẶC
VÀ LỰC MA SÁT TRONG Ổ TRỤC QUAY
1. CƠ SỞ LÝ THUYẾT:
h
1
ω
h
2
Xét vật tại điểm A và C ta có : ∆ W
T
= f
ms
h
1
2
→ f
ms
h
1
2
mg
h
1
− h
2
h
1
2
Xét vật tại điểm B ta có : I =
m d
2
g t
2
h
2
h
1
h
1
2
2. PHƯƠNG PHÁP ĐO:
BÁO CÁO
THÍ NGHIỆM VẬT LÝ
B
A
h
1
A
B
C
h
2
C
B
h
2
ln I =ln
md
2
g t
2
h
2
h
1
1
2
⇔ ln I =ln m + 2 ln d −ln 4 + ln g + 2 ln t + ln h
2
−ln h
1
−ln
h
1
2
∂ m
m
∂d
d
∂ g
g
∂t
t
1
h
1
h
1
2
2
h
2
h
1
2
∆ m
m
∆ d
d
∆ g
g
∆ t
t
1
h
1
h
1
2
2
h
2
h
1
2
∆ m
m
∆ d
d
∆ g
g
∆ t
t
1
h
1
h
1
2
2
h
2
h
1
2
δ
I
∆ m
m
∆ g
g
∆ t
t
∆ d
d
h
1
h
1
2
∆ h
1
h
2
h
1
2
∆ h
2
h
d ( mm ) ∆ d ( mm ) t
∆ t ( s ) h
2
( mm ) h
2
( mm )
d
∆ d
t
∆ t
h
2
∆ h
2
d =
d
1
2
3
4
5
=8,148 ( mm )
1
d = |
d
1
− d |
2
d =
|
d
2
− d
|
3
d =
|
d
3
− d
|
4
d = |
d
4
− d |
5
d =
|
d
5
− d
|
∆ d =
1
d + ∆
2
d + ∆
3
d + ∆
4
d + ∆
5
d
=0,010 ( mm )
∆ d =( ∆ d )
dc
t =
t
1
2
3
4
5
=7,514 ( s )
1
t =
|
t
1
− t
|
2
t =
|
t
2
− t
|
3
t = |
t
3
− t |
4
t =
|
t
4
− t
|
5
t = |
t
5
− t |
∆ t =
1
t + ∆
2
t + ∆
3
t + ∆
4
t + ∆
5
t
=0,005 ( s )
∆ t =( ∆ t )
dc
2
h 2
h
2 ( 1 )
2 ( 2 )
2 ( 3 )
2 ( 4 )
2 ( 5 )
mm
1
h
2
|
h
2 ( 1 )
− h
2
|
2
h
2
|
h
2 ( 2 )
− h
2
|
3
h
2
|
h
2 ( 3 )
− h
2 |
− 3
( kg ⋅ m
2
δ
I
∆ m
m
∆ g
g
∆ t
t
∆ d
d
|
h
1
h
1
2
|
∆ h
1
|
h
2
h
1
2
|
∆ h
2
|
|
|
|
∆ I = I ∙δ
I
− 3
− 5
( kg ⋅m
2
f
ms
= f
ms
± ∆ f
ms
− 3
− 3
− 5
kg. m
2