Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

all this is it your aa, Summaries of Egyptian Art and Architecture

tgis it hti tia fdaioa fao j aoipjhfoa

Typology: Summaries

2024/2025

Uploaded on 05/12/2025

shaan-nagra
shaan-nagra 🇺🇸

1 document

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Intro to Linear Algebra – Final Exam
with Solutions
Problem 1
Given the system below, create the augmented matrix and solve using row reduction:
x - 2x + 3x = 7
2x + x - x = 1
-3x + 4x + 2x = 10
Determine if the system is consistent and classify the solution.
Solution
Augmented matrix:
[1 -2 3 | 7]
[2 1 -1 | 1]
[-3 4 2 | 10]
After row reducing, we get a unique solution:
x = 1, x = 2, x = 0
The system is consistent with a unique solution.
Problem 2
Let a = [1; 2; -1], a = [0; -1; 2], b = [3; 0; 5]
(a) Is b in the span of {a , a }?
(b) Solve A = b, if possible.𝑥
Solution
(a) Form [A|b] = [[1 0 | 3]; [2 -1 | 0]; [-1 2 | 5]]. Row reduce: leads to inconsistency.
So, b is not in the span.
(b) No solution exists.
Problem 3
Given A = [[1 2 -1]; [2 4 -2]; [0 1 1]]:
(a) Is A = 0 linearly dependent?𝑥
(b) Find general solution.
(c) Are columns linearly independent?
Solution
(a) Yes, row reduction shows free variables.
(b) General solution: x = s[-2;1;0] + t[1;0;1]
(c) No, columns are linearly dependent.
pf3

Partial preview of the text

Download all this is it your aa and more Summaries Egyptian Art and Architecture in PDF only on Docsity!

Intro to Linear Algebra – Final Exam

with Solutions

Problem 1

Given the system below, create the augmented matrix and solve using row reduction: x ₁ - 2x ₂ + 3x ₃= 7 2x ₁ + x ₂ - x ₃= 1 -3x ₁ + 4x ₂ + 2x ₃= 10 Determine if the system is consistent and classify the solution.

Solution

Augmented matrix: [1 -2 3 | 7] [2 1 -1 | 1] [-3 4 2 | 10] After row reducing, we get a unique solution: x ₁ = 1, x ₂ = 2, x ₃= 0 The system is consistent with a unique solution.

Problem 2

Let a ₁ = [1; 2; -1], a ₂= [0; -1; 2], b = [3; 0; 5] (a) Is b in the span of {a , a }?₁ ₂ (b) Solve A 𝑥= b, if possible.

Solution

(a) Form [A|b] = [[1 0 | 3]; [2 -1 | 0]; [-1 2 | 5]]. Row reduce: leads to inconsistency. So, b is not in the span. (b) No solution exists.

Problem 3

Given A = [[1 2 -1]; [2 4 -2]; [0 1 1]]: (a) Is A 𝑥= 0 linearly dependent? (b) Find general solution. (c) Are columns linearly independent?

Solution

(a) Yes, row reduction shows free variables. (b) General solution: x = s[-2;1;0] + t[1;0;1] (c) No, columns are linearly dependent.

Problem 4

Let A = [[2 1]; [5 3]]: (a) Find A ¹⁻ (b) Verify A * A ¹ = I⁻ (c) Solve A 𝑥= [1; 4]

Solution

(a) det = 23 - 51 = 1 → A ¹ = [[3 -1]; [-5 2]]⁻ (b) A * A ¹ = I⁻ (c) x = A ¹ * b = [5; -6]⁻

Problem 5

Let A = [[1 3 1]; [2 6 2]; [-1 -3 -1]]: (a) Basis for Col(A) and Nul(A) (b) Find rank and dim (c) Is A invertible?

Solution

(a) Basis Col(A): {[1;2;-1]}, Nul(A): span{[-3;1;0], [-1;0;1]} (b) Rank = 1, dim Nul = 2 (c) Not invertible

Problem 6

Find eigenvalues and basis for each eigenspace of A = [[4 1]; [2 3]]

Solution

Char poly: ( -5)( -2) = 0 →λ λ λ= 5, 2 λ =5: eigenspace = span{[1;1]}, λ=2: span{[-1;1]}

Problem 7

Diagonalize A from #6 and compute A³

Solution

P = [[1 -1]; [1 1]], D = [[5 0]; [0 2]], A³ = P D³ P ¹ = [[109 -78]; [156 -109]]⁻

Problem 8

Let u = [1;2;2], y = [4;1;3]. (a) Find proj (y)ₐ (b) Write y = ŷ + z (c) Distance between y and line thru u