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Major Quiz 2 Solutions for MA140: Calculus I - Prof. Paula R. Stickles, Quizzes of Calculus

Solutions to major quiz 2 for the calculus i (ma140) course. It includes explanations for finding the roots of a polynomial function, the derivative of a function, and the equation of the tangent line. It also covers finding derivatives using limits and without using product or quotient rules.

Typology: Quizzes

Pre 2010

Uploaded on 08/04/2009

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MA140-01
2/11/09
Major Quiz 2
_________________, come on down!
Show all your work and explain your answers completely. I cannot give partial credit for answers that are both wrong and
unexplained. Even correct "bottom line" answers that are mysterious and unsupported will not be considered completely correct. Show
me what you are thinking. Try to keep your answers neat and organized so that I can follow them easily.
1.) Explain why f(x) has a root in the interval [0,1] where
5
( ) 2 3 1
f x x x
= + โˆ’
.
๎˜ ๎˜‚๎˜ƒ๎˜๎˜„๎˜…๎˜†๎˜‡๎˜ˆ๎˜‰๎˜Š๎˜
๎˜
Since f(x) is a polynomial function, it is continuous everywhere, and thus, continuous on the closed
interval [0,1].
5 5
( ) 2 3 1 (0) 2(0) 3(0) 1 1
f x x x f
= + โˆ’ ๎˜= + โˆ’ = โˆ’
and
5 5
( ) 2 3 1 (1) 2(1) 3(1) 1 4
f x x x f
= + โˆ’ ๎˜= + โˆ’ =
Since f is a continuous function on the closed interval [0,1] and the signs of f(0) and f(1) alternate, the
function must cross the x axis in the interval. Thus, there is a zero in the interval [0,1].
2.) Using the definition of the derivative, find
'( )
where
( ) 2
f x x
= +
.
๎˜ ๎˜‚๎˜‹๎˜๎˜„๎˜…๎˜†๎˜‡๎˜ˆ๎˜‰๎˜Š๎˜
0
( ) ( )
lim
h
f x h f x
h
โ†’
+ โˆ’
0
1
lim
2 2
h
x h x
โ†’
+ + + +
3.)
Find and equation of the line tangent to the graph of y = 4x
2
โ€“ 3x + 1 when x = -1.
๎˜‚๎˜ƒ๎˜๎˜„๎˜…๎˜†๎˜‡๎˜ˆ๎˜‰๎˜Š๎˜
' 8 3
y x
= โˆ’
If x = -1, y = 8.
1 1
( )
y y m x x
โˆ’ = โˆ’
8 ( 11)( ( 1))
y x
โˆ’ = โˆ’ โˆ’ โˆ’
11 3
y x
= โˆ’ โˆ’
0
2 2
lim
h
x h x
h
โ†’
+ + โˆ’ +
0
2 2 2 2
lim
2 2
h
x h x x h x
hx h x
โ†’
+ + โˆ’ + + + + +
โ‹…
+ + + +
( )
0
lim
2 2
h
h
h x h x
โ†’
+ + + +
1
2 2
x
+
'( 1) 8( 1) 3 11 Slope of tangent at x = -1
is -11
y
โˆ’ = โˆ’ โˆ’ = โˆ’
pf3

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Download Major Quiz 2 Solutions for MA140: Calculus I - Prof. Paula R. Stickles and more Quizzes Calculus in PDF only on Docsity!

2/11/

Major Quiz 2 _________________, come on down! Show all your work and explain your answers completely. I cannot give partial credit for answers that are both wrong and unexplained. Even correct "bottom line" answers that are mysterious and unsupported will not be considered completely correct. Show me what you are thinking. Try to keep your answers neat and organized so that I can follow them easily. 1.) Explain why f(x) has a root in the interval [0,1] where f ( ) x = 2 x^5 + 3 x โˆ’ 1.      Since f(x) is a polynomial function, it is continuous everywhere, and thus, continuous on the closed interval [0,1]. f ( ) x = 2 x^5^ + 3 x โˆ’ 1  f (0) = 2(0)^5 + 3(0) โˆ’ 1 = โˆ’ 1 and f ( ) x = 2 x^5 + 3 x โˆ’ 1  f (1) = 2(1) 5 + 3(1) โˆ’ 1 = 4 Since f is a continuous function on the closed interval [0,1] and the signs of f(0) and f(1) alternate, the function must cross the x axis in the interval. Thus, there is a zero in the interval [0,1].

2.) Using the definition of the derivative, find f '( ) x where f ( ) x = x + 2.    

0

lim h f x h f x โ†’ h

0 lim 1 h โ†’ (^) x + h + 2 + x + 2

3.) Find and equation of the line tangent to the graph of y = 4x^2 โ€“ 3x + 1 when x = -1.    y ' = 8 x โˆ’ 3 If x = -1, y = 8. y โˆ’ y 1 (^) = m x ( โˆ’ x 1 ) y โˆ’ 8 = โˆ’( 11)( x โˆ’ โˆ’( 1))

y = โˆ’ 11 x โˆ’ 3

0

lim h x h x โ†’ h

0 lim 2 2 2 2 h 2 2

x h x x h x โ†’ h (^) x h x

        • (^0) ( )

lim h 2 2

h โ†’ (^) h x + h + + x + 1 2 x + 2

y '( 1)โˆ’ = 8( 1)โˆ’ โˆ’ 3 = โˆ’11 Slope of tangent at x = -1 is -

2/11/

4.) Determine f '( ) x in each of the following. In part a, you are not allowed to use the product or quotient rules.      

(a)

2 3

x x

f x

x

(^5 3 2 3 )

f ( ) x 3 x 4 x x

โˆ’

f x x x x

โˆ’ (^) โˆ’

OR

3 2 3 3

f x x

x x x

(b) f ( ) x = ( x^4 โˆ’ 2 x^3^ + x )( 3 x^2 โˆ’ 4 x + ฯ€)

Recall

1

x = x^2

3 2 1 2 4 3

f x x x x x x ฯ€ x x x x

(c)

3 4

x x

f x

x x

2 4 3 3 4 2

x x x x x x

f x

x x

5.) Find h '(2)if h x ( ) = ( f โ‹… g )( ) x , if f (2) = 6, g (2) = 7, f '(2) = โˆ’3, g '(2) = 8.

   

h '( ) x = f '( ) x g x ( ) + f ( ) x g '( ) x h '(2) = f '(2) g (2) + f (2) g '(2) h '(2) = โˆ’( 3)(7) +(6)(8) h '(2) = 27