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Material Type: Exam; Professor: Aktas; Class: Topics & Meth of General Phys; Subject: Physics; University: University of North Carolina - Charlotte; Term: Unknown 1989;
Typology: Exams
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with water. A laser beam starts from side A of the container and enters the
water at position x. You can ignore the thin walls of the container.
a. If x = 15 cm, does the laser beam refract back into the air through side B
or reflect from the side B back into the water?
b. Find the minimum value of x for which the laser beam passes through the
side B and emerges into the air. Index of refraction of water is 1.330.
screen 2.0 m behind the slits. Each slit is 0.040 mm wide and they are separated by 0.
mm. Calculate the positions of first five bright interference fringes relative to the center.
How many bright fringes are seen in the central diffraction envelope?
constructive interference in the reflected light if the film is illuminated with light whose
wavelength in air is 600 nm.
field components given as,
1
0
sin ω t
2
0
sin( ω t + φ)
By using the method of phasors show that the intensity variation on the screen is
0
cos
2
π d
λ D
y
Where I 0
is the intensity of incident beam, d is the slit separation, D is the distance
between the screen and the slit. Use small angle approximation.
Some useful formulas
y ( x , t ) = A sin( kx − ω t + ϕ)
cos α + cos β = 2 cos(
α + β
)cos(
α − β
ω = 2 π f =
2 π
, k =
2 π
λ
, v =
μ
v =
ω
k
= λ f =
λ
f = f
v ± v
D
v ± v
S
sin( α + β) = sin α cos β + sin β cos α
Δ φ
2 π
Δ d
λ
, c =
m
m
ε
0
μ
0
μ
0
ave
, Δ p =
c
Δ p
Δ t
c
, p
r
, ε
0
− 12
F / m , μ
0
− 6
H / m
€
λ
n
=
λ
n
, ±
1
f
= ±
1
o
±
1
i
, m = −
i
o
=
′ h
h
, n
1
sin θ
1
= n
2
sin θ
2
c
2
= a
2
2
− 2 ab cos θ , θ : Angle between a and b.
Double slit path diffrence = d sin θ
Single slit path diffrence = a sin θ
Thin film path diffrence = 2 t
for small θ , sin θ ≈ tan θ