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5 Solved Problems on Intrinsic Transcription - Exam 2 | BI 381, Exams of Molecular biology

Material Type: Exam; Professor: Gathman; Class: Molecular Genetics; Subject: Biology; University: Southeast Missouri State University; Term: Spring 2008;

Typology: Exams

Pre 2010

Uploaded on 08/08/2009

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BI 381 Exam 2 Spring 2008
Instructions: Relax.
1. a. (10 points) Explain how intrinsic transcription termination occurs in a prokaryote.
b. (10 points) Describe the process of intron removal and exon splicing in a eukaryotic
RNA transcript. Be as specific as possible about the snurps involved and the sequence of
events.
b. (10 points) Describe the process of forming the poly-A tail on a eukaryotic RNA
transcript, being as specific as possible about the enzymes involved and the sequence of
events.
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BI 381 Exam 2 Spring 2008 Instructions: Relax.

  1. a. (10 points) Explain how intrinsic transcription termination occurs in a prokaryote. b. (10 points) Describe the process of intron removal and exon splicing in a eukaryotic RNA transcript. Be as specific as possible about the snurps involved and the sequence of events. b. (10 points) Describe the process of forming the poly-A tail on a eukaryotic RNA transcript, being as specific as possible about the enzymes involved and the sequence of events.
  1. Figures 1c and 2b from Kozmin et al. are shown below. Stars mark groups of genotypes that were significantly different; fig. 1c shows three groups that are different from each other, and fig. 2b shows two groups that are different from each other. The functions of the wild type alleles of the genes referred to here are as follows: OGG codes for 8- oxoguanine N-glycosylase, RAD14 codes for lesion-binding protein required for yeast NER, and PHR1 codes for photolyase. ber- indicates a strain with mutant alleles of several genes encoding various N-glycosylases, including ogg. Fig 1c. Fig. 2b. Questions on the next page refer to these graphs.

4 a. (20 points) In the table below, indicate whether each mutant organism will be able to grow when placed on each medium, by putting + for growth of the organism and - for no growth of the organism. Please make them clear so I can read them. Notes: Compounds B and F are combined by condensation to form H; compound C is hydrolyzed to form compounds D and E. The organism must either make or receive both compound K and compound J in order to grow. Each mutant is mutant for only one gene (coding for one enzyme). Growth on minimal medium supplemented with compound: Mutant (None) A B C D E F G H I J K 1 2 3 4 5 6 7 8 b. (5 points) If a colony of mutant 4 cells is placed on minimal medium, what compound(s) will accumulate inside the mutant cells? Just answer, don't explain. c. (5 points) Suppose you had a double mutant strain of this organism, containing the mutant alleles from both mutants 2 and 7. Would it grow on any of the supplemented media listed above? If so, which one(s)? Just answer, don't explain.

  1. (10 points) For each of the following lesions, pick the mutagen most likely to produce it and the repair system most likely to repair it in E. coli. Put the letter of the mutagen and the number of the repair system in the appropriate box. Explanations are not required, but if you want to justify an answer you can write in the comments box. Mutagens: a. UVA b. UVB c. x-rays d. alkylating agent (e.g. EMS) e. 5-BU (a base analog) f. intercalating agent g. none(spontaneous). Repair systems:
    1. Direct reversal
    2. Base excision repair
    3. Nucleotide excision repair
    4. Mismatch repair
    5. None Lesion Mutagen Repair Comments (optional) deamination of cytosine to uracil large adduct on a base methyl group on a base oxidation of a base cyclobutane pyrimidine dimer