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Millersville university mathematics department's quiz 2 for math 161, focusing on identifying discontinuities and finding limits. Students are required to find the discontinuity of the function f(x) = x^2 - 1 with x - 1, explain their answers, and determine the limit of the function 4 - x / (x - 2)^2 as x approaches 2 from the left.
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Millersville University Name Mathematics Department MATH 161, Quiz 2 January 23, 2004
Please answer the following questions. Your answers will be evaluated on their correctness, completeness, and use of mathematical concepts we have covered. Please show all work and write out your work neatly. Answers without supporting work will receive no credit.
f (x) =
x^2 − 1 x − 1
Explain your answer fully. Since f (x) is undefined at x = 1, it must have a discontinuity at x = 1. We can see that the
lim x→ 1
x^2 − 1 x − 1
= lim x→ 1
(x − 1)(x + 1) x − 1 = (^) xlim→ 1 (x + 1) = 2.
Since the two-sided limit exists as x → 1, f (x) has a removeable discontinuity at x = 1.
lim x→ 2 −
4 − x (x − 2)^2 As x → 2 −^ the numerator approaches 2. As x → 2 −^ the denominator approaches 0, but is always positive. Thus the fraction is positive as x → 2 −^ and grows to positive infinity. Hence we write lim x→ 2 −
4 − x (x − 2)^2