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An experiment to determine the latent heat of fusion of ice using a calorimeter. The theory behind phase changes and the mathematical expression to calculate the latent heat of fusion. It also provides the procedure for conducting the experiment and analyzing the results.
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A small amount of ice is placed in a calorimeter containing water. By knowing the masses of the ice, the water, and the calorimeter, and the resulting temperature change after the ice melts, the latent heat of fusion of ice is found.
When heat is added to a substance, a temperature change is generally observed to occur. The heat added, Q. that causes a temperature change T is
Q = mc T (1)
where rn is the mass of the substance and c is its specific heat, which is assumed to be constant over the temperature change, T
However, situations exist where heat added to a substance does not caust- a change in the temperature. In these cases, the added heat causes a change in phase to occur. Two common changes in phase are from solid to liquid and from liquid to gas. The amount of heat required to accomplish a phase change is called the heat of transformation. More specifically, for a solid to liquid phase change, it is referred to as the heat of fusion; and for a liquid to gas phase change, the heat of vaporization. The heat of fusion or vaporization can be expressed mathematically as
Q – mL (2)
where L is the latent heat of fusion or vaporization, depending on the phase transition that occurs.
In this experiment, an ice cube of mass mt, assumed to be at 0oC, is placed in a calorimeter containing a mass of water rnw. at temperature Tl,. After the ice cube melts, the temperature of the system is T 2. When the heat lost is equated to the heat gained, and the resulting equation solved for the latent heat of fusion L, the result is
t
w w c c t w m
mc T T mc T T mc T L
where cw is the specific heat of water (4.19 J/g oC) and mccc, is the water equivalent of the calorimeter.
In order to calculate the heat of fusion of ice from (3), it is necessary to first determine the water equivalent of the calorimeter. The value mccc is found by mixing known quantities of warm water and cool water in the calorimeter.
Suppose the Calorimeter contains a mass of warm water mww, at temperature Tw. If a mass of ool water mcw, at temperature Tc is mixed with the warm water in the calorimeter. thermal equilibrium will be established at an intermediate temperature T When the heat lost and the heat gained are equated, and the resulting equation solved for the water equivalent of the calorimeter. the expression becomes
m c T T m c T T L w
cw w c ww w w
where cw is the specific heat of water.
o calorimeter with cork stopper o double-pan balance o slotted weights o 0-50 0 C thermometer, 1 0 C o container for water o 0-100 0 C thermometer, 2 0 C o crushed ice o ice cubes
There is an attempt in this experiment to minimize heat loses and gains by using a calorimeter. Heat transfers can be further minimized by removing the cork stopper from the calorimeter only when necessary and only for a short time. Compensation is made for the heat losses -or gains that inevitably occur. By starting the calorimeter and contents at a temperature above room temperature, the heat loss to the environment by the warm water is offset by the heat gained by the cool water or ice that is added to the calorimeter. An attempt is also made to produce a final equilibrium temperature at or close to room temperature. Figure 1. The Calorimeter a) Find the mass of the empty calorimeter with the 0- 50 oC thermometer inserted in the cork. (Refer to Figure 1.)
b) Obtain water from the tap that is approximately 10 oC above room temperature. Pour this water into the calorimeter until it is 1/3 full. Wait for thermal equilibrium to be established, then record the